16x^2-46x-35=0

Solution for 16x^2-46x-35=0 equation:

16x^2-46x-35=0

a = 16; b = -46; c = -35;
Δ = b2-4ac
Δ = -462-4·16·(-35)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4356}=66$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-66}{2*16}=\frac{-20}{32}
=-5/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+66}{2*16}=\frac{112}{32}
=3+1/2
$